二氧化硅负载硅钨钼酸催化合成丁醛1,2-丙二醇缩醛  

Catalytic Synthesis of Butyraldehyde 1,2-Propanediol Acetal with H_4SiW_6Mo_6O_(40)/SiO_2

作　　者：杨水金[1] 喻莉[1] 丁水朋[1] 章天骏[1] 

机构地区：[1]湖北师范学院化学与环境工程学院,黄石435002

出　　处：《精细石油化工进展》2013年第1期30-33,共4页Advances in Fine Petrochemicals

基　　金：湖北省教育厅中青年科研基金资助项目(Q20112507)

摘　　要：简要介绍了二氧化硅负载硅钨钼酸催化剂的制备方法,并以SiO2负载硅钨钼酸为催化剂,丁醛和1,2-丙二醇为原料合成丁醛1,2-丙二醇缩醛,用正交实验法考察了反应物料摩尔比、催化剂用量、带水剂环己烷用量、反应时间等因素对产品收率的影响。结果表明,在丁醛与1,2-丙二醇摩尔比1∶1.4,催化剂用量占反应物料总质量的0.8%,带水剂环己烷用量8 mL,反应时间60 min的优化条件下,丁醛1,2-丙二醇缩醛的收率可达91.6%。The preparation of H4SiW6Mo6O40/SiO2 as catalyst was briefly decribed.Butyraldehyde 1,2-propanediol acetal was synthesized form butyraldehyde and 1,2-propanediol in the presence of H4SiW6Mo6O40/SiO2.The factor influencing the synthesis were discussed through orthogonal experiment.The optimum conditions were determined as follows:molar ratio of butyraldehyde to 1,2-propanediol 1:1.4,catalyst dosage 0.8%(based on the total mass of feed stocks),the volume of cyclohexane 8 mL,and the reaction time 60 min.H4SiW6Mo6O40/SiO2 is an excellent catalyst for synthesizing butyraldehyde 1,2-propanediol acetal with the yield up to 91.6%.

关 键 词：丁醛1 2-丙二醇缩醛 H4SIW6MO6O40 SIO2 催化 

分 类 号：O643.32[理学—物理化学]