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作 者:王忠兵[1] 李凤霞[1] 汪洋 陈春年[1] 张大伟[1]
机构地区:[1]合肥工业大学化学与化工学院,合肥230009 [2]南京时恒电子科技有限公司,南京211121
出 处:《硅酸盐学报》2015年第6期776-780,共5页Journal of The Chinese Ceramic Society
基 金:安徽省自然科学基金(1208085ME85)资助
摘 要:采用固相法制备Ni–Mn–Sn–O系单相尖晶石结构化合物。使用X-射线衍射技术确定了该体系的成相范围和温度,并判定该尖晶石结构的阳离子分布。结果表明:Ni元素摩尔含量在15%以下时,形成四方尖晶石相;在15%~30%之间时形成立方尖晶石相;大于30%时则易析出NiO相。Sn元素的含量对成相温度有重要影响,其含量越多,成相温度越高。但当Sn元素含量达到30%以上时,则不能进入尖晶石结构中。Sn元素以Sn4+的形式占据尖晶石结构中的B位,导致其电阻率和热敏常数B值急剧增加。The Ni–Mn–Sn–O compounds with a spinel structure were prepared via solid state reaction.The composition and temperature of spinel structure formed were investigated by X-ray diffraction.The cations distribution in the spinel structure was also clarified.The results show that the Ni–Mn–Sn–O compounds form a tetragonal-spinel structure when the content of Ni element is less than 15%(in mole fraction),form a cubic spinel when the content of Ni element is 15%–30% and generate a NiO phase when the content of Ni element is more than 30%.The content of Sn element has a great effect on the temperature of spinel structure formed.The more Sn element content,the higher temperature for the formation of spinel structure will be.The solubility of Sn element in spinel is limited when the content of Sn element is less than 30%.The Sn4+ ion can occupy the B-site of spinel structure,leading to the increase of resistivity and thermal constant B.
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