（Bi，Pb）_2Sr_2（R，Ce）_2Cu_2O_（10＋δ）超导体碘嵌入后  

STRUCTURAL CHANGES AND Tc VAINTION OF THE SUPERCONDUCTORS (Bi, Pb)_2Sr_2 (R, Ce)_2Cu_2O_(10+X) UPON IODINE INTERCALATION

作　　者：朱文杰[1] 黄玉珍[1] 钞希旭 贾顺连[1] 赵忠贤[1] 

机构地区：[1]中国科学院物理研究所,陕西师范大学物理系

出　　处：《低温物理学报》1994年第2期108-112,共5页Low Temperature Physical Letters

摘　　要：超导体系（Ｐｂ１．８Ｐｂ０．２）Ｓｒ２（Ｒ１．７Ｃｅ０．３）Ｃｕ２Ｏ１０＋δ（Ｒ＝Ｎｄ，Ｓｍ，Ｇｄ，Ｙ）经碘嵌入后形成一个Ｃ轴拉长的新结构．每个式子可含一个碘原子．碘使每个（ＢｉＯ）双层膨胀３．４至３．６Ａ，体系氧含量减少从而导致Ｔｃ下降．与其它超导体系相比，碘嵌入的样品的（ＣｕＯ２）面间距很大，但Ｒ＝Ｓｍ，Ｎｄ的样品仍然超导，这意味着（ＣｕＯ２）面间偶台对超导性产生并不重要．AbstractIodine has ben intercalated in the superconductors (Bi, Pb)2Sr2(R, Ce)2Cu2O10+x (R=Nd, Sm, Gd and Y), forming a new c expoded structure. Each formula is saturated by approxhate one iodine atom. Iodine causes the expansion of each Bio bilayer by 3. 4 to 3. 6 angstrom and the loss of oxygen which is believed to account for the depression of Tc. Although the distance between CuO2 sheets is so large as compared with that of other cuprate superconductors, the intercalated samples of R=Nd and Sm still remain superconducting. This may suggest that CuO2 direct interplanar coupling is not so linportant for occurrence of superconductivity.

关 键 词：超导体 碘 超导转变温度 结构 

分 类 号：O511.1[理学—低温物理]