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作 者:PeiXinCHEN ShiJieLU
机构地区:[1]DepartmentofMathematics,NanjingUniversityofScienceandTechnology,Nanjing210094,P.R.China [2]DepartmentofMathematics,ZhejiangUniversity,Hangzhou310027,P.R.China
出 处:《Acta Mathematica Sinica,English Series》2005年第1期9-12,共4页数学学报(英文版)
摘 要:If K ∩ AlgL is weak. dense in AlgL, where K is the set of all compactoperators in B(H), is completely distributive? In this note, we prove that there is a reflexivesubspace lattice L on some Hilbert space, which satisfies the following conditions: (a) F(AlgL) isdense in AlgL in the ultrastrong operator topology, where F(AlgL) is the set of all finite rankoperators in AlgL; (b) L isnt a completely distributive lattice. The subspace lattices that satisfythe above conditions form a large class of lattices. As a special case of the result, it easy to seethat the answer to Problem 7 is negative.If K ∩ AlgL is weak. dense in AlgL, where K is the set of all compactoperators in B(H), is completely distributive? In this note, we prove that there is a reflexivesubspace lattice L on some Hilbert space, which satisfies the following conditions: (a) F(AlgL) isdense in AlgL in the ultrastrong operator topology, where F(AlgL) is the set of all finite rankoperators in AlgL; (b) L isnt a completely distributive lattice. The subspace lattices that satisfythe above conditions form a large class of lattices. As a special case of the result, it easy to seethat the answer to Problem 7 is negative.
关 键 词:Completely distributive subspace lattice Ultrastrong topology COUNTEREXAMPLE
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