约束条件下铜合金加热时的塑性变形及变形功  

Plastic Deformation and Plastic Deformation Work of Copper Alloy under Condition of Confining Pressure in Heating Process

作　　者：崔慧然[1] 杨蕴林[1] 王长生[1] 

机构地区：[1]河南科技大学材料科学与工程学院,河南洛阳471003

出　　处：《河南科技大学学报（自然科学版）》2005年第1期1-5,共5页Journal of Henan University of Science And Technology:Natural Science

基　　金：激光技术国家重点实验室开放基金资助项目(2001-0110)

摘　　要：固态焊接加热过程中,受约束焊件因胀大变形不能进行而产生等效塑性压缩变形(EPCD)。本文以H62和QCr0.5铜合金为研究对象,对EPCD及相应的变形功进行了试验研究。结果表明:等效塑性应变ε和变形功W的大小主要与加热温度θ和预压应力σ0有关,σ0一定时,ε随θ升高而增大,其中H62黄铜当θ<550℃和θ>700℃时,ε随θ升高而线性增大,θ在550～700℃之间时,ε的增幅减小;QCr0.5铬青铜的ε随θ升高线性增大,但增幅较H62小;θ一定时,两种铜合金的ε均随σ0增加而近似线性增大;两种铜合金的W随θ的升高而减小,随σ0的增大而增大,且H62的增幅明显大于QCr1.5;当σ0和θ一定时,W随ε的增加呈指数关系增大。Equivalent plastic compress deformation (EPCD) is produced because the constrained work piece has no expansion in the heating process of the solid-state welding.The experimental researches on EPCD and its corresponding plastic deformation work of H62 brass and QCr0.5 bronze's are conducted.The results show that the heating temperature θ and the prepressing stress σ_0 are mainly related to equivalent plastic compress strain ε and plastic deformation work W: if σ_0 is invariable,ε increases with θ rising,and to H62 brass,when θ<550℃ or θ>700℃,ε increases linearly with θ rising.Meanwhile,when θ is in the range of 550℃ and 700℃,ε increases more slowly.To QCr0.5,ε increases linearly with θ rising,but it increases more slowly than that of H62's.When θ is constant,ε of the two kinds of copper alloy's increases linearly with σ_0 rising.W of the two kinds of copper alloys decreases with θ rising and increases with σ_0 increasing,but obviously ε of H62's increases more quickly than that of (QCr0.5's).In addition,if θ and σ_0 are unchangeable,W increases with ε increasing,the curve of　W-ε seems like parabola.

关 键 词：铜合金 固态焊接 塑性变形 铬青铜 焊件 黄铜 塑性应变 增幅 增加 QC 

分 类 号：TG146.11[一般工业技术—材料科学与工程]