NdCl_3-CdCl_2-HCl-H_2O的相平衡及其固相化合物的研究  

Phase Equilibrium of the NdCI_3-CdCI_2-HCI-H_2O System at 298.15 K and Characterization of New Compounds

作　　者：乔占平[1] 卓立宏[1] 郭应臣[1] 王惠[2] 

机构地区：[1]南阳师范学院化学系,河南南阳473061 [2]西北大学化学系,陕西省物理无机化学重点实验室,西安710069

出　　处：《物理化学学报》2005年第11期1249-1253,共5页Acta Physico-Chimica Sinica

基　　金：河南省自然科学基金资助项目(0311021900)~~

摘　　要：测定了四元系NdCl3-CdCl2-HCl-H2O(298.15K)的相平衡溶度数据,绘制了相应的溶度图.该四元系是由4个固相区CdCl2·H2O(原始盐)、9CDCl2·NdCl3·20H2O、5CDCl2·NdCl3·13H2O、NdCl3·6H2O(原始盐)组成的复杂体系.用X射线粉末衍射及TG-DTG和荧光光谱对9CdCl2·NdCl3·20H2O和5CdCl2·NdCl3·13H2O进行了研究.荧光研究表明,化合物9CdCh·NdCl3·20H2O具有微弱的荧光强度,5CdCl2·NdCl3·13H2O的荧光强度则相对大于9CDCl2·NdCl3·20H2O的.对X射线粉末衍射进行了指标化.The equilibrium solubility of the quaternary system NdCl3-CdCl2-HCl-H2O was determined at 298.15 K and the corresponding equilibrium diagram was constructed. The result shows that the quaternary system was complicated with four equilibrium solid phases CdCl2·H2O, 9CdCl2-NdCl3·20H2O （9：1 type）, 5CdCl2-NdCl3·13H2O （5：1 type） and NdCl3·6H2O. The two new compounds, 9CdCl2·NdCl3-20H2O and 5CdCl2·NdCl3·13H2O, have not yet been reported in literatures, and they were congruently soluble in the quaternary. The two new compounds have been prepared from the system and characterized by XRD, TC-DTG, and fluorescence （FL） spectra. Result of FL spectra showed that the 9CdCl2·NdCl3·20H2O has weak fluorescence intensity, and 5CdCl2·NdCl3·13H2O exhibited larger fluorescence intensity than 9CDCl2·NdCl3·20H2O. X-ray powder diffraction patterns were indexed.

关 键 词：四元体系 相平衡 CDCL2 NDCL3 荧光光谱 

分 类 号：O642.4[理学—物理化学]