检索规则说明:AND代表“并且”;OR代表“或者”;NOT代表“不包含”;(注意必须大写,运算符两边需空一格)
检 索 范 例 :范例一: (K=图书馆学 OR K=情报学) AND A=范并思 范例二:J=计算机应用与软件 AND (U=C++ OR U=Basic) NOT M=Visual
作 者:郭文生[1] 胡志泉[1] 王忠华[1] 郭放[1]
出 处:《渤海大学学报(自然科学版)》2007年第4期289-296,共8页Journal of Bohai University:Natural Science Edition
基 金:国家自然科学基金项目(No:20372031).
摘 要:1,1,6,6-四苯基-2,4-己二炔-1,6-二醇(D.D)与茴香醛在不同的结晶条件下形成主客体分子物质的量比分别为2:1和1:2的包结物晶体。x-射线单晶衍射测试结果表明,在2:1(h/g)包结物晶体中,D.D通过形成闭合氢键网,构筑了1(?) zigzag主体分子框架超结构,形成的隧道框架对茴香醛具有识别作用;在1:2(h/g)包(?)物晶体中,主体分子采取0维框架超结构,按2_1次螺旋轴呈zigzag形状排列,茴香醛分子与主体分子通过OH…O强氢键作用进入主体分子构筑的隧道。它们互为超分子异构体。产生异构体的原因是,在前者包结物晶体中,主体分子采取邻位交叉式构象,而在后者的包结(?)晶体中,主体分子采取对位交叉式构象,因此,它们又是超分子构象异构体。Inclusion crystals with molar ratio (host/guest) of 2 : 1 and 1:2 are formed by 1,1,6,6 -tet- raphenylhexa -2,4 -diyne - 1,6 -diol( D. D) with p -anisaldehyde in different crystal conditions respectively. The results of x - ray single crystal diffraction show that 1 D zigzag ribbon host framework is constructed by D. D molecules through closed H - bonds network formed themselves in inclusion crystal with molar ratio of 2 :1 (host/guest), and p -anisaldehyde molecules are packed into tunnel enelosodby 1 D zigzag ribbon, while in inclusion crystal with molar ratio of I :2 (host/guest), the framework of D. D. molecules is 0 D. structure, and arrayed in zigzag shape according to 21 screw ro/ation axis, and through molecular interaction of OH 0 = C strong H - bonds, p - anisaldehyde molecules are packed into tunnel enelosod by D.D. molecules. They are supramoleeular isomers to each other. In the former inclusion crystal, D. D. molecule adopted gauche con- formation, while in the latter inclusion crystal, D.D. molecule adopted antiperiplanar conformation, and these are the cause of supramoleeular isomers formed. Therefore, they are regarded as supramoleeular conformation isomers.
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在链接到云南高校图书馆文献保障联盟下载...
云南高校图书馆联盟文献共享服务平台 版权所有©
您的IP:216.73.216.60