UV-H_2O_2工艺降解饮用水中内分泌干扰物-双酚A  

Degradation of endocrine disruptor-bisphenol in drinking water by combination process of UV-H_2O_2

作　　者：高乃云[1] 芮旻[1] 徐斌[1] 王虹[1] 伍海辉[1] 

机构地区：[1]同济大学污染控制与资源化研究国家重点实验室,上海200092

出　　处：《哈尔滨工业大学学报》2008年第2期328-332,共5页Journal of Harbin Institute of Technology

基　　金：国家高技术研究发展计划资助项目(863-2002AA601130);国家科技攻关计划重大资助项目(2003BA808A17)

摘　　要：针对饮用水中内分泌干扰物双酚A对环境造成的污染问题,采用UV、H2O2及UV-H2O2联用工艺去除饮用水中双酚A.研究表明,单独的H2O2不能有效氧化去除BPA;单独UV光照射对BPA有一定去除效果,但去除率有限;而UV-H2O2联用工艺对饮用水中BPA具有很好的去除效果.在原水BPA质量质量浓度为1 mg/L左右、UV光强133.9μW/cm2、H2O2投加量10 mg/L和反应时间40 min条件下,BPA的去除率可达到98.3%.UV-H2O2联合工艺降解饮用水中BPA的动力学方程式可表达为ρ=ρe-(0.0002[H2O2]1.0002[UV]0.8048)t,该模型可较好模拟UV-HO联合工艺对BPA的降解效果.To degrade endocrine disruptor bisphenol A in drinking water, the process of UV, H2O2 and combination of the two was studied respectively. The results showed that BPA could not be effectively removed by H2O2 oxidation only and the removal efficiency of BPA was very limited by UV radiation alone. However, the combination process of UV - H2O2 could achieve good results for BPA degradation. The removal efficiency of BPA could be up to 98.03 % under the conditions that the BPA concentration in raw water, the intensity of UV radiation, the dosage of H2O2 and the HRT were 1 mg/L, 133.9 μW/cm^2, 10 mg/L and 40 minutes respectively. The degradation kinetics equation can be expressed as ρ = ρ0e^-（0. 0002[H2O2]1.0002[UV]0.8048） t, which can simulate the degradation effects of BPA through the combination process of UV - H2O2.

关 键 词：双酚A UV辐照 H2O2 反应动力学 饮用水 

分 类 号：X328[环境科学与工程—环境工程]