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出 处:《石油炼制与化工》2010年第4期54-57,共4页Petroleum Processing and Petrochemicals
基 金:国家自然科学基金资助项目(20566004);国家科技攻关计划资助项目(2001BA323C)
摘 要:在以硅胶负载铌酸为主催化剂、三(3,6-二氧杂庚基)胺为助催化剂的催化体系的作用下,以环戊烯和水为原料,通过水合加成反应合成了环戊醇。考察了原料配比、反应温度、反应时间及催化剂用量等因素对环戊醇收率的影响。确定适宜的反应条件为:环戊烯1.0 mol,n(环戊烯):(n水)=1:4,反应温度120℃,反应时间4.0 h,硅胶负载铌酸主催化剂用量4.0 g,三(3,6-二氧杂庚基)胺助催化剂0.8 g。在此反应条件下,环戊醇收率为68.6%。Cyclopentanol was synthesized from cyclopentene and water through hydration reaction using HNb3O8·H2O/SiO2 as main catalyst and tris(dioxa-3, 6-heptyl)amine(TDA-1 )as cocatalyst. The effects of raw materials ratio, reaction temperature, reaction time and catalyst dosage on the yield of cyclopentanol were investigated and optimum reaction conditions were obtained. Under the optimum conditions of a cyclopentene amount of 1.0 mol, a molar ratio of cyclopentene to water of 0.25, a reaction temperature of 120 ℃, a reaction time of 4.0 h, a main catalyst dosage of 4.0 g and a cocatalyst dosage of 0.8 g, the yield of cyclopentanol reached 68.6%.
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