取代吲哚-3-甲醛与3-甲基-1-苯基-5-吡唑啉酮的固相缩合反应  

Solid Phase Condensation between Substituted Indole-3-formaldehyde and 1-Phenyl-3-methyl pyrazol-5-one

作　　者：王俊岭[1] 马军营[1] 

机构地区：[1]河南科技大学化工与制药学院,河南洛阳471003

出　　处：《化学世界》2011年第3期159-161,共3页Chemical World

摘　　要：在无溶剂、无催化剂、微波辐射条件下,取代吲哚-3-甲醛与3-甲基-1-苯基-5-吡唑啉酮通过固相Knoevenagel缩合反应合成了一系列4-(取代吲哚基-3-次甲基)-3-甲基-1-苯基-5-吡唑啉酮,产物结构经IR,1H NMR确证。最佳反应条件为:n(吲哚-3-甲醛)∶n(3-甲基-1-苯基-5-吡唑啉酮)=1.1∶1.0,微波辐射时间6 min,微波功率500 W,产率57.8%～76.0%。A series of 4-（substituted-indole-3-methylene）-1-phenyl-3-methyl pyrazol-5-one were synthesized by Knoevenagel condensation between substituted indole-3-formaldehyde and 1-phenyl-3-methyl pyrazol-5-one under microwave irradiation without solvent and catalyst.The structures were confirmed by IR and ～1H NMR.The optimum reaction conditions were as follows： the power of microwave was 500 W;the time of irradiation was 6 min;n（substituted indole-3-formaldehy-de）∶n（1-phenyl-3-methyl pyrazol-5-one） was 1.1∶1.0.The yield was 57.8%～76.0%.

关 键 词：取代吲哚-3-甲醛 吡唑啉酮 KNOEVENAGEL缩合 固相合成 

分 类 号：O621.3[理学—有机化学]