BaMoO_4:Eu^(3+)发光材料的制备及光谱特性研究  

Synthesis and Luminescent Characteristic of BaMoO_4:Eu^(3+)

作　　者：邱桂明[1] 许成科[2] 黄翀[1] 

机构地区：[1]汕头大学理学院物理系,广东汕头515063 [2]衡阳师范学院物理与电子信息科学系,湖南衡阳421008

出　　处：《光谱学与光谱分析》2011年第5期1200-1203,共4页Spectroscopy and Spectral Analysis

基　　金：国家自然科学基金项目(60778032)资助

摘　　要：利用高温固相法制备了BaMoO4:Eu3+发光材料,采用X射线衍射(XRD)和荧光光谱仪对样品进行测试。结果表明,在800℃时得到BaMoO4纯相,属四方晶系。激发光谱由一个宽带和处在350 nm后的若干个线状谱组成,宽带归属于Eu3+—O2-电荷迁移吸收带(CT),线状谱属于Eu3+的f—f激发跃迁吸收。发射光谱由5D0—7F1(591 nm),5D0—7F2(615 nm),5D0—7F3(654 nm)和5D0—7F4(702 nm)四组峰组成,其红光5D0—7F2辐射跃迁发射最强,对应Eu3+的电偶极跃迁。The BaMoO4∶Eu3＋ phosphors were synthesized by solid-state method and were characterized by X-ray diffraction（XRD） and photoluminescence spectra.XRD analysis confirmed the formation of BaMoO4 at 800 ℃ and exhibited a tetragonal crystal structure.The excitation spectrum of samples showed one broad band and some peaks located behind 350 nm.The former was attributed to the charge transfer transition of Eu3＋—O2-,while the latter belonged to the f—f transitions of Eu3＋ ions.The emission spectrum shows four peaks at 591,615,654 and 702 nm,respectively.The dominant peak is located at 615 nm due to the 5D0—7F2 electric dipole transition of Eu3＋.

关 键 词：BaMoO4:Eu3+ 发光材料 光致发光 LED 

分 类 号：O644[理学—物理化学]