检索规则说明:AND代表“并且”;OR代表“或者”;NOT代表“不包含”;(注意必须大写,运算符两边需空一格)
检 索 范 例 :范例一: (K=图书馆学 OR K=情报学) AND A=范并思 范例二:J=计算机应用与软件 AND (U=C++ OR U=Basic) NOT M=Visual
作 者:冯若强[1,2] 丁静鹄[1] 李庆祥[3] 叶继红[1]
机构地区:[1]东南大学混凝土与预应力混凝土结构教育部重点实验室,南京210096 [2]华南理工大学亚热带建筑科学国家重点实验室,广州510500 [3]广东省建筑科学研究院,广州510500
出 处:《东南大学学报(自然科学版)》2012年第2期328-333,共6页Journal of Southeast University:Natural Science Edition
基 金:国家自然科学基金资助项目(50908044);国家杰出青年基金资助项目(51125031);江苏省自然科学基金资助项目(SBK201123270);亚热带建筑科学国家重点实验室开放基金资助项目(2011KA05)
摘 要:分析了肋环型单层曲板网壳结构的风荷载和风振响应,并对采用不同方法计算结构等效静风荷载的精度进行了比较.风洞试验结果表明:肋环型单层曲板网壳结构屋面主要受负风压作用;但在90°风向角下,由于体育馆受前方入口建筑的影响,屋盖边缘局部出现正风压.风振响应分析结果表明:有多阶振型参与结构的风致振动,高阶模态影响不可忽略;为保证结构表面所有节点位移准确,结构的模态耦合项不能忽略.但如果只保证较大位移处的准确性,忽略模态耦合项的SRSS方法也是可取的.利用LRC惯性力法和改进LRC方法计算肋环型单层曲板网壳结构的等效静风荷载,可以保证所有风向角下节点的最大位移等效,但不能保证所有节点的位移等效.The wind pressure and the wind-induced vibration of a single-layer Geiger lattice shell with curved plate are analyzed. Different methods are used to calculate the equivalent static wind load, and the calculation accuracy are compared. The results of the wind tunnel experiment showthat the wind pressure is mostly negative on the single-layer Geiger lattice shell with curved plate. But under the 90° wind direction, because of the flow obstruction of the front building, the positive pressure appears on some area of the roof' s edge. The wind-induced response analysis results showthat many modes make contribution to the structural wind-induced response, and the higher modes should be considered. Subjected to the fluctuating wind load, the mode coupling should be consid- ered in order to obtain a good accuracy of the wind-induced response for all the structural nodes. Ifonly the accuracy of the larger displacement is needed, the square root sum of square (SRSS) meth- od which ignores the mode coupling can be also used. It is found that both the load-response correla- tion(LRC) with inertia force method and the modified LRC method for calculating the equivalent static wind load of the single-layer Geiger lattice shell with curved plate can ensure the equivalence of the largest displacements rather than all the nodal displacements.
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在链接到云南高校图书馆文献保障联盟下载...
云南高校图书馆联盟文献共享服务平台 版权所有©
您的IP:216.73.216.28