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机构地区:[1]辽宁石油华工大大学化学与材料科学学院,辽宁抚顺113001
出 处:《化工科技》2012年第2期25-28,共4页Science & Technology in Chemical Industry
基 金:辽宁省自然科学基金项目(2011402008)
摘 要:利用丙烯酸和苯甲酰氯合成丙烯酰氯(AC),AC再与N,N-二甲基乙二胺(DMAEA)合成可聚合单体N,N-二甲基丙烯酰乙二胺。通过红外光谱和核磁共振谱证实产物的结构。考察原料的物质的量比、不同缚酸剂的用量与浓度、稀释N,N-二甲基乙二胺和丙烯酰氯的二氯甲烷的量、加料顺序对产品收率的影响,得出适宜的实验条件为:n(DMAEA)∶n(AC)=1∶1.2,缚酸剂w(NaOH)=25%的用量为25mL,稀释N,N-二甲基乙二胺和丙烯酰氯的二氯甲烷的量分别为80mL和45mL,加料顺序为先加N,N-二甲基乙二胺的二氯甲烷溶液,再加缚酸剂。在上述条件下,产品最高收率可达83%。Acryloyl chloride(AC)was synthesized with acrylic acid and benzoyl chloride.N-[(dimethylamino) ethyl]acrylamide,a kind of polymerizable monomer,was prepared with(AC)and 2-dimethylaminoethylamine(DMAEA).The product was identified by IR and 1H NMR.The effects of different reaction conditions(mass ratio of n(DMAEA) to n(AC),kind and quantity of acid-binding agent,solvent usage and feeding sequence) on the yield of the product were investigated.Optimum reaction parameters for thus synthesis were obtained as follows.mass ratio of n(DMAEA) to n(AC) is 1∶1.2.25 mL NaOH solution(25%) is used as acid-caputor.The amount of dichloromethane for diluting DMAEA and AC is 80 mL and 45 mL,respectively.The feeding sequence is that acid-binding agent followed with dichloromethane.Under these reaction conditions,the yield of product is 83%.
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