引信解除保险距离兰利法试验最小样本量  被引量:3

Minimum Samples of Fuze Arming Distance Test of Langlie

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作  者:叶美凤[1] 王雨时[1] 闻泉[1] 

机构地区:[1]南京理工大学机械工程学院,江苏南京210094

出  处:《探测与控制学报》2012年第3期35-41,共7页Journal of Detection & Control

摘  要:针对在现行标准中没有详尽规定兰利法试验样本量的问题,基于感度用数理统计试验相关理论及数理统计学原理,提出判定兰利法试验最小样本量的方法,得到检验最小样本量公式、范围及其确定流程。理论分析及Matlab仿真表明:引信解除保险距离兰利法试验同时满足均值和方差精度要求的最小样本量范围是[8,24];方差和均值估计精度并非随试验样本量增加而提高;均值、试验响应点和标准差的估计受均值精度影响较大;方差和引信解除保险距离上、下限的估计比传统兰利法要好,但是无法从根本上解决方差系统偏低的问题。The sample amount of Langlie test was not detailed in current standards, the determination of the minimum samples of Langlie test was proposed in this paper. By drawing on documents related to mathematical statistics test and mathematical statistics, the minimum sampling number of Langlie test of fuze arming distance was acquired. The sample number of Langlie test of fuze arming distance was [8,24], and the estimate of vari- ance and mean for arming distance did not increase with the test samples increasing. The estimate of response level of mean, and variance was affected seriously by mean precision. The veracity of variance, the maximum and minimum response level were higher than that of traditional Langlie method, however the lower variance could not be amended fundamentally.

关 键 词:引信 解除保险距离 兰利法 计算机仿真 数理统计学 数理统计试验方法 

分 类 号:TJ430[兵器科学与技术—火炮、自动武器与弹药工程]

 

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