铂铼重整催化剂硫酸根污染的研究  

STUDIES ON SULFATE ION CONTAMINATION OF Pt-Re REFORMING CATALYSTS

作　　者：毛学军[1] 孙作霖[2] 张大庆[2] 

机构地区：[1]镇海炼油化工股份有限公司,浙江镇海315207 [2]石油化工科学研究院,北京100083

出　　处：《石油学报（石油加工）》2000年第2期25-32,共8页Acta Petrolei Sinica(Petroleum Processing Section)

摘　　要：选取铂铼重整催化剂 ,模拟工业再生过程中催化剂上硫酸根的形成机理 ,制备了含有硫酸根的催化剂样品。以正庚烷为模型化合物 ,在连续加压微反色谱装置上对样品进行活性评价。实验表明 ,硫酸根不但抑制了催化剂的酸性和金属功能 ,同时加快了催化剂的失活速率 ,使芳构化活性与选择性大幅度下降。高铼铂比 (n(Re) / n(Pt)=2 )催化剂对硫酸根的敏感程度大于 n(Re) / n(Pt) =1的催化剂。催化剂表面结构表征表明 ,硫酸根的形成并不导致铂晶粒长大 ,它对催化剂金属功能的抑制是由于部分被还原为硫化氢而使金属过硫化所致 ;硫酸根的形成引起了催化剂上氯含量下降 ,使催化剂表面 L酸强度降低 ,造成催化剂补氯困难 ,但并不破坏载体的结构。Bimetallic Pt Re reforming catalyst samples containing different amounts of sulfate ion were prepared by simulating the formation of sulfate on reforming catalysts during industrial regeneration n Heptane as the model compound was employed to test activity and selectivity of the samples on continuous flow pressure microreactor chromatograph system As a result, sulfate ion suppressed both acid function and metal function of the catalyst samples and accelerated deactivation Catalysts with n (Re)/ n (Pt) =2 were more sensitive to sulfate than catalysts with n (Re)/ n (Pt)=1 The characterization of catalyst surface structure proved that the sulfate ion formation didn't affect platinum particle size and the suppression of metal function was due to excessive sulfidation of the metal fraction by H 2S produced during the reduction of the sulfated catalysts with hydrogen Though the formation of sulfate ion did not destroy the support structure, it caused a decline in chlorine content and surface Lewis acid sites and thus the difficulties for chlorine regulation

关 键 词：催化重整 硫酸根 铂铼催化剂 炼油 催化剂失活 

分 类 号：TE624.92[石油与天然气工程—油气加工工程] O643.362[理学—物理化学]