检索规则说明:AND代表“并且”;OR代表“或者”;NOT代表“不包含”;(注意必须大写,运算符两边需空一格)
检 索 范 例 :范例一: (K=图书馆学 OR K=情报学) AND A=范并思 范例二:J=计算机应用与软件 AND (U=C++ OR U=Basic) NOT M=Visual
出 处:《电子机械工程》2014年第2期19-22,共4页Electro-Mechanical Engineering
摘 要:研究了热流密度为100 W/cm2的固态组件的基板和壳体的等效导热系数、厚度和横截面面积对整个组件的冷却装置的热阻的影响。基板和壳体的导热系数从160 W/(m·K)提高到800 W/(m·K)时,冷却装置总热阻分别下降约1.2℃/W和0.55℃/W,下降比例分别为33.3%和15.5%;基板厚度从0.4 mm增加到1.6 mm时,冷却装置总热阻下降约0.78℃/W,下降比例为22.0%;基板横截面面积从0.42 cm2增加到2.1 cm2时,冷却装置总热阻下降约0.52℃/W,下降比例为15.1%;壳体厚度从0.8 mm增加到2.4 mm时,冷却装置总热阻下降约0.43℃/W,下降比例为11.6%;以上各种情况中冷却装置总热阻下降趋势为先急后缓。对于目前的组件而言,参考上述结果进行优化,将使组件的冷却得到明显改善。The effect of equivalent thermal conductivity, thickness and cross-sectional area of the base and the shell of solid state module ( heat flux is 100 W/cm2 ) on the thermal resistance of the cooling device of the module is studied in this paper. The thermal resistance of the cooling device reduces about 1.2 ℃/W and 0.55℃/W when the thermal conductivity of the base and the shell increase from 160 W/(m @ K) to 800 W/(m @ K) respectively, and the reducing percentage is 33.3% and 15.5% respectively. The ther- mal resistance of the cooling device reduces about 0.78 ℃/W when the thickness of the base increases from 0.4 mm to 1.6 mm, and the reducing percentage is 22.0%. The thermal resistance of the cooling device reduces about 0.52℃/W when the cross-sectional area of the base increases from 0.42 cm2 to 2.1 cm2, and the reducing percentage is 15.1%. The thermal resistance of the cooling device reduces about 0.43 ℃/W when the thickness of the shell increases from 0.8 mm to 2.4 mm, and the reducing percentage is 11.6%. The above change rates are all rapid at first and slow latter. As to the electronic module nowadays, the cooling will be improved a lot if the module is optimized according to the above result.
分 类 号:TK124[动力工程及工程热物理—工程热物理]
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在链接到云南高校图书馆文献保障联盟下载...
云南高校图书馆联盟文献共享服务平台 版权所有©
您的IP:216.73.216.3