检索规则说明:AND代表“并且”;OR代表“或者”;NOT代表“不包含”;(注意必须大写,运算符两边需空一格)
检 索 范 例 :范例一: (K=图书馆学 OR K=情报学) AND A=范并思 范例二:J=计算机应用与软件 AND (U=C++ OR U=Basic) NOT M=Visual
机构地区:[1]南京航空航天大学理学院数学系,南京210016
出 处:《西安文理学院学报(自然科学版)》2015年第1期22-26,共5页Journal of Xi’an University(Natural Science Edition)
摘 要:重点研究考虑资源最大需求上限的鹰鸽博弈中合作和竞争的演化动态.我们假设参与博弈的鸽策略者对资源的最大需求量为m1,参与博弈的鹰策略者对资源的最大需求量为m2(m1<m2),资源总量为V(0<V<m1+m2),斗争导致受伤的代价为c(c>0).首先求出当2m1<m2时,资源总量V的取值不同时的收益矩阵.随后求出当m2<2m1时,资源总量V的取值不同时的收益矩阵.基于收益矩阵最后研究引入需求上限的鹰鸽博弈中合作和竞争的演化动态.Our focus is on the evolution dynamics of cooperation and competition in the hawk and dove game within the upper limit of resource demand. If the maximum resource demand of the dove strategists is m1 ,meanwhile,that of the hawk strategists is m2 (m1 〈 m2) and the total resource is V(O 〈 V 〈 m1 + m2 ), the cost of fighting wounds will be c ( c 〉 0 ). Firstly, under the condition of 2m1 〈 m2, the total resource V is measured against non-simultaneous income ma- trix; Secondly,under the condition of m2 〈 2m1, the total resource V is measured against non- simultaneous income matrix. Lastly, based on income matrix, evolution dynamics of cooperation and competition in the hawk and dove game within the upper limit of resource demand are stud- ied.
分 类 号:O211.9[理学—概率论与数理统计]
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在链接到云南高校图书馆文献保障联盟下载...
云南高校图书馆联盟文献共享服务平台 版权所有©
您的IP:3.142.83.171