维生素C对碘猝灭荧光素荧光抑制作用的研究  

Study of Inhibition of Vitamin C on Iodine quenches Fluorescence of Fluorescein

作　　者：夏雁青[1] 李卫宾 

机构地区：[1]枣庄学院化学化工与材料科学学院,山东枣庄277160 [2]山东公信安全科技有限公司,山东枣庄277101

出　　处：《广东化工》2015年第9期61-62,共2页Guangdong Chemical Industry

摘　　要：碘能够与荧光素发生取代反应,由于重原子效应使荧光素的荧光被显著猝灭.而维生素C能够抑制这一反应,它可与碘发生氧化还原反应,使体系荧光恢复.通过实验,我们发现当维生素C浓度在0.8×10-6 mol·L-1～3.0×10-6 mol·L-1范围内时,荧光的恢复和维生素C浓度具有良好的线性关系,线性回归方程：F=990.17C＋1221.96（C单位为10-6 mol·L-1）,相关系数r=0.99138.并检测了稀释后达能牌饮料中维生素C的浓度,取得满意结果.Iodine can undergo substitution reaction with fluorescein, and fluorescence is significantly quenched due to heavy atom effect. Vitamin C can inhibit this reaction because it can undergo redox reaction with Iodine. Our experimental results showed that there was a good linear relationship between fluorescence recovery and concentration of Vitamin C within the range of 0.8 × 10-6 mol.L-1-3.0×10-6 mol·L-1. The linear equation was F=990.17C＋1221.96 （C units of 10-6 mol·L-1）, and the correlation coefficient r = 0.99138. Finally we tested the concentration of Vitamin C in diluted Danone beverage, and achieved satisfactory results.

关 键 词：荧光素 碘 荧光 维生素C 

分 类 号：TQ[化学工程]