饮酒促进TA2小鼠乳腺癌的发生及机制探讨  

Alcohol promotes the tumorigenesis of spontaneous breast cancer in TA2 mice and the possible potential mechanism

作　　者：徐陌 陈志军 桂照华[1] 陈丹蕾[1] 赵浩东[1] 杨帆[1] 汪思应[1] 

机构地区：[1]安徽医科大学病理学与病理生理学教研室,合肥230032 [2]重庆市云阳县人民医院,重庆4045000

出　　处：《中国实验动物学报》2017年第5期563-566,共4页Acta Laboratorium Animalis Scientia Sinica

摘　　要：目的探讨酒精是否促进小鼠乳腺癌的发生及可能的作用机制。方法建立饮酒TA2小鼠模型,用ANALOX AM1酒精分析仪检测TA2小鼠血液的酒精浓度,确保动物模型的建立;观察比较酒精组TA2小鼠(饮用含2%酒精的无菌水)与对照组TA2小鼠(饮用不含酒精的无菌水)的乳腺癌发生率、肿瘤的生长速度以及肿瘤的大小;酶联免疫法(ELASA)检测两组小鼠血清中雌激素水平的差异。结果饮酒组TA2小鼠自发乳腺癌的比例显著增加(P<0.05),成瘤平均天数明显缩短(P<0.05),生成肿瘤的重量和体积均有增加但差异无显著性(P>0.05)。饮酒组TA2小鼠体内的雌激素水平明显升高(P<0.05)。结论酒精促进TA2小鼠乳腺癌的发生,该作用可能通过雌激素水平的增加来实现。Objective To explore whether alcohol promotes the development of breast cancer in TA2 mice and the possible potential mechanism. Methods Thirty-two 6-8-week old nulliparous female TA2 mice were randomly divided into control and ethanol-exposure groups,16 mice in each group. The mice of the ethanol-exposure group were given 2%ethanol in drinking water,and the mice of control group received regular drinking water. Serum ethanol concentration in the TA2 mice was measured using an ANALOX AM1 alcohol analyzer. The incidence of breast cancer,tumor growth rate and tumor size of the ethanol-exposure and control groups were observed and compared. The estrogen levels of the two groups was detected by enzyme-linked immunosorbent assay（ ELASA）. Results Compared with the control group,the tumor formation rate of spontaneous breast cancer in the alcohol-exposure group was significantly increased（ 62. 5% vs. 43. 75%,P〈0. 05）,the average number of days of tumor formation was shortened（ 285 days vs. 335 days,P〈0. 05）,the tumor weight and volume were increased but not significant（ P〉0. 05）,and the level of estrogen in the ethanol-exposure mice was significantly higher than that in the control group（ P〉0. 05）. Conclusions Alcohol promotes the tumorigenesis of spontaneous breast cancer in TA2 mice,which may be associated to the increase of estrogen levels.

关 键 词：酒精 TA2小鼠 乳腺癌 雌激素 

分 类 号：Q95-33[生物学—动物学]