胍基锆酰胺配合物与四氯化碳的反应生成氯化锆胍基衍生物  

Formation of Zirconium Chloride Guanidinate Complexes from the Reaction of their Amide Analog with CCl4

作　　者：Bhavna Sharma 薛子陵 Bhavna Sharma;XUE Zi-Ling(Department of Chemistry,the University of Tennessee,Knoxville,Tennessee 37996,USA)

机构地区：[1]田纳西大学化学系,诺克斯维尔市37996,美国

出　　处：《无机化学学报》2020年第6期1157-1162,共6页Chinese Journal of Inorganic Chemistry

基　　金：美国国家科学基金(No.CHE-1362548,CHE-1900296)资助。

摘　　要：四氯化碳与Zr(NMe2)2[iPr NC(NMe2)NiPr]2(1)反应先生成中间体Zr Cl(NMe2)2[iPr NC(NMe2)NiPr]2(2),然后生成Zr Cl2[iPr NC(NMe2)NiPr]2(3)。该反应可能是自由基反应。另外,配合物2可由Zr Cl(NMe2)3与二异丙基碳二亚胺i Pr-N=C=N-iPr反应制备。对配合物2进行了核磁共振(NMR)和元素分析。Reaction of CCl4 with zirconium amide guanidinate Zr(NMe2)2[iPr NC(NMe2)NiPr]2(1)has been found to give Zr Cl(NMe2)[iPr NC(NMe2)NiPr]2(2)as an intermediate and later Zr Cl2[iPr NC(NMe2)NiPr]2(3).The reaction is likely radical in nature.Complex 2 has been independently prepared from the reaction of Zr Cl(NMe2)3with diisopropylcarbodiimide,iPr-N=C=N-iPr,and characterized by nuclear magnetic resonance(NMR)and elemental analysis.

关 键 词：锆 氯 酰胺配合物 

分 类 号：O641.4[理学—物理化学] O614.412[理学—化学]