检索规则说明:AND代表“并且”;OR代表“或者”;NOT代表“不包含”;(注意必须大写,运算符两边需空一格)
检 索 范 例 :范例一: (K=图书馆学 OR K=情报学) AND A=范并思 范例二:J=计算机应用与软件 AND (U=C++ OR U=Basic) NOT M=Visual
作 者:冯国会[1] 赵佳绩 黄凯良[1] FENG Guohui;ZHAO Jiaji;HUANG Kailiang(Shenyang Jian Zhu University,Shenyang 110168,China)
机构地区:[1]沈阳建筑大学,沈阳110168
出 处:《建筑科学》2020年第6期50-55,共6页Building Science
基 金:“十三五”国家重点研发计划“近零能耗建筑技术体系及关键技术开发”(2017YFC0702600);国家自然科学基金项目(51778376)。
摘 要:以某超低能耗示范建筑为例,结合该示范建筑地源热泵系统夏季运行的数据,分析了地源热泵系统供回水温差大、机组COP值小的问题并提出解决方案;根据运行数据,测试期间累计制冷量约为54 650.8 kW·h;前期地源热泵供回水温差在15℃左右,机组COP值在2.5~3.75之间,解决后供回水温差在2~4℃左右,机组COP值在4.0~5.0之间。通过本次运行测试分析,为超低能耗建筑中的地源热泵的合理运行提供参考。In this paper,an ultra-low energy demonstration building was taken as an example,and the data of ground source heat pump system operation in summer were used to analyze the problems of large temperature difference between the supply and return water of the ground source heat pump system and the small COP value of the unit,and solutions were proposed accordingly.It can be known from the operation data that the cumulative cooling capacity during the test is of 54 650.8 kW·h approximately,the temperature difference between the supply and return water of the ground source heat pump in the early stage is of 15 ℃ approximately,and the COP value of the unit is between 2.5 and 3.75.After the problems have been solved,the temperature difference between the supply and return water was controlled at 2 ℃ to 4 ℃ approximately,and the COP value of the unit is between 4.0 and 5.0.Based on the analysis of this operation test,the reference was provided to the reasonable operation of the ground source heat pump in the ultra-low energy buildings.
关 键 词:超低能耗建筑 地源热泵 能耗 COP值 问题分析
分 类 号:TU831[建筑科学—供热、供燃气、通风及空调工程]
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在链接到云南高校图书馆文献保障联盟下载...
云南高校图书馆联盟文献共享服务平台 版权所有©
您的IP:216.73.216.49