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作 者:权国卿 王舜和 宋杰 QUAN Guo-qing;WANG Shun-he;SONG Jie(Southwest Mucipal Engineering Design&Reasearch Institute of China,Chengdu 610036,China;Universtar Science&Technology(Shenzhen)Co.,Ltd.)
机构地区:[1]中国市政工程西南设计研究总院有限公司,四川成都610036 [2]宇星环保工程有限公司,广东佛山528311
出 处:《西南给排水》2023年第6期5-11,共7页Southwest Water & Wastewater
摘 要:多级A/O生物处理系统的总氮去除率由污泥回流比R,总分段数n及流量分配系数比q三者决定。根据公式可知,分段数n及污泥回流比R越大,流量分配系数比q越小,总氮去除率越高。污泥回流比R主要控制生物池中污泥浓度,当采用二沉池进行泥水分离时,一般可取0~100%。流量分配系数比q可根据进水碳氮比及理论碳氮比计算得出。通常情况下,增大n可以提高总氮去除率。但在n≥4以后,继续增加分段数,去除率的增加值不到0.026。因此工程上总分段数一般不超过4。需要注意的是n、R及q的取值并不是互相独立的,而是存在内在关联。The total nitrogen removal rate of the multi-stage A/O biological treatment system is de-termined by the sludge reflow ratio R,the total segment number n,and the flow distribution coefficient ratio q.According to the formula,the greater the number of segments n and the sludge return ratio R,the smaller the flow distribution coefficient ratio q,and the higher the total nitrogen removal rate.Usual-ly,the flow distribution coefficient ratio q can be calculated based on the influent carbon-nitrogen ratio and the theoretical carbon-nitrogen ratio.The sludge reflux ratio R mainly controls the sludge concen-tration in the biological tank.When the secondary settling tank is used for sludge-water separation,it is generally O~100%.Although increasing n can improve the removal rate of total nitrogen,according to the image,after n≥4,the minimum removal rate of total nitrogen is 75.4%.If the number of segments continues to increase,the increase in removal rate is less than 0.026.Therefore,the total number of seg-ments in the project generally does not exceed 4.In the case where the number of segments cannot be in-creased,the total nitrogen removal rate can still be improved by reducing q,but carbon sources need to be added.It should be noted that the values of n,R and q are not independent of each other,but are in-herently related.
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