检索规则说明:AND代表“并且”;OR代表“或者”;NOT代表“不包含”;(注意必须大写,运算符两边需空一格)
检 索 范 例 :范例一: (K=图书馆学 OR K=情报学) AND A=范并思 范例二:J=计算机应用与软件 AND (U=C++ OR U=Basic) NOT M=Visual
机构地区:[1]武汉科技大学城市建设学院,湖北 武汉 [2]陕西大唐高科机电科技有限公司,陕西 西安
出 处:《建模与仿真》2024年第2期1908-1920,共13页Modeling and Simulation
摘 要:本文通过实验与数值模拟方法,对45˚弯管和不同曲率半径比(R/D = 1, 2, 3, 4, 5)的90˚弯管阻力系数进行了研究,分析了弯管内压力分布、速度矢量、二次流动及流动轨迹等规律,并重点分析了不同弯管曲率半径与管径之比下的弯管中流场流动特点。结果表明:RNG k-ε湍流模型的模拟结果与实验吻合较好。同一Re下,R/D越大局部阻力系数ξ越小,R/D在1~3范围内增大曲率可以明显降低局部阻力系数,再增大曲率局部阻力减小不明显。In this paper, the resistance coefficient of 45˚ bending pipe and 90˚ bending pipe with different ratio of curvature radius (R/D = 1, 2, 3, 4, 5) was studied by experimental and numerical simulation methods, and the laws of pressure distribution, velocity vector, secondary flow and flow trajectory in bending pipe were analyzed, and the characteristics of flow field in bending pipe with different ratio of curvature radius to diameter were emphatically analyzed. The results show that the simulation results of RNG k-ε turbulence model agree well with the experimental results. Under the same Re, the larger the R/D, the smaller the local drag coefficient. When R/D increases the curvature in the range of 1~3, the local drag coefficient can be significantly reduced, and when R/D increases the curvature, the local drag is not significantly reduced.
关 键 词:45°弯管 90°弯管 阻力实验 数值模拟 曲率半径比 局部阻力系数ξ
分 类 号:TP3[自动化与计算机技术—计算机科学与技术]
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在链接到云南高校图书馆文献保障联盟下载...
云南高校图书馆联盟文献共享服务平台 版权所有©
您的IP:216.73.216.38