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作 者:Pooya Daneshmand Kamyar Mirzavaziri Madjid Mirzavaziri Pooya Daneshmand;Kamyar Mirzavaziri;Madjid Mirzavaziri(Ferdowsi University of Mashhad, International Campus, Mashhad, Iran;National Organization for Development of Exceptional Talents (NODET) I, Mashhad, Iran;Department of Pure Mathematics, Ferdowsi University of Mashhad, Mashhad, Iran)
机构地区:[1]Ferdowsi University of Mashhad, International Campus, Mashhad, Iran [2]National Organization for Development of Exceptional Talents (NODET) I, Mashhad, Iran [3]Department of Pure Mathematics, Ferdowsi University of Mashhad, Mashhad, Iran
出 处:《Open Journal of Discrete Mathematics》2016年第2期99-104,共6页离散数学期刊(英文)
摘 要:Let n be a positive integer. A permutation a of the symmetric group of permutations of is called a derangement if for each . Suppose that x and y are two arbitrary permutations of . We say that a permutation a is a double derangement with respect to x and y if and for each . In this paper, we give an explicit formula for , the number of double derangements with respect to x and y. Let and let and be two subsets of with and . Suppose that denotes the number of derangements x such that . As the main result, we show that if and z is a permutation such that for and for , then where .Let n be a positive integer. A permutation a of the symmetric group of permutations of is called a derangement if for each . Suppose that x and y are two arbitrary permutations of . We say that a permutation a is a double derangement with respect to x and y if and for each . In this paper, we give an explicit formula for , the number of double derangements with respect to x and y. Let and let and be two subsets of with and . Suppose that denotes the number of derangements x such that . As the main result, we show that if and z is a permutation such that for and for , then where .
关 键 词:Symmetric Group of Permutations Derangement Double Derangement
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