检索规则说明:AND代表“并且”;OR代表“或者”;NOT代表“不包含”;(注意必须大写,运算符两边需空一格)
检 索 范 例 :范例一: (K=图书馆学 OR K=情报学) AND A=范并思 范例二:J=计算机应用与软件 AND (U=C++ OR U=Basic) NOT M=Visual
出 处:《动物学报》2005年第2期294-298,共5页ACTA ZOOLOGICA SINICA
基 金:"十五"国家科技攻关项目 (No. 2001BA710B);国家自然科学基金面上项目 (No.30400266);江苏省教育厅高校自然科学研究基金 ( No. 03KJB180155 ) 资助~~
摘 要:用连锁分析法对乙烷基亚硝基脲(ENU) 诱变获得的两例被毛突变小鼠(snthr 1Bao及snthr 2Bao) 的突变基因进行定位。选择平均分布于小鼠基因组且在C57BL/6J和DBA/2 间有差异的39 个微卫星对B6D2F1 互交得到的稀毛F2 进行全基因组扫描。扫描了9个微卫星后发现snthr 1Bao突变基因与D9Mit243 的LOD值为7 73。突变基因被定位于9号染色体。在此基础上又选择了D9Mit355 和D9Mit18 两个微卫星进行检测, 并扩大F2 的数量至145只。结果发现, snthr 1Bao与D9Mit18间无1 例重组, 稀毛突变基因与该微卫星紧密连锁, 距着丝点71cM。同理, 将snthr 2Bao突变基因也定位在与snthr 1Bao相近的区域。检索发现snthr 1Bao是一尚未克隆的新基因。Two new scant hair mice, named snthr -1Bao and snthr -2Bao, had been obtained by ENU-induced mutagenesis, and the method of linkage analysis was employed to map these mutant genes. We selected 39 microsatellites, distributed on the mouse chromosome and with difference between C57BL/6J and DBA/2, to scan the genome after discrimination of the scant hair mice in the F 2 of snthr -1Bao, the offspring of B6D2F1. After we had screened 9 microsatellites, we found that the log odds score (LODS) between snthr -1Bao and D9Mit243 was 7.73, which indicated that the mutant gene was located on chromosome 9. And then we selected microsatellites D9Mit355 and D9Mit18 to test all samples again, and the amount of the scant hair F 2 was up to 145.The LODS of snthr -1Bao and D9Mit18 was 87.30 and no one case of recombination was found. Data showed that mutation gene of snthr -1Bao closely linked D9Mit18 about 71 cM from the centromere. In the same way, snthr -2Bao was mapped nearby snthr -1Bao. After searching the Mouse Genomic Database, snthr-1Bao is found to be a new gene that has not been cloned.
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在载入数据...
正在链接到云南高校图书馆文献保障联盟下载...
云南高校图书馆联盟文献共享服务平台 版权所有©
您的IP:216.73.216.71