微波催化剂协同作用合成乳酸乙酯  

Synthesis of Ethyl Lactate Under the Condition of Microwave Irradiation and Catalyst

作　　者：刘红梅[1] 贾丹丹[1] 牛少莉[1] 宋爱君[1] 

机构地区：[1]河北科技师范学院化学系,河北秦皇岛066600

出　　处：《河北科技师范学院学报》2007年第1期33-36,共4页Journal of Hebei Normal University of Science & Technology

摘　　要：采用微波辐射技术,在无水CaCl2催化下,乳酸与乙醇常压下直接合成乳酸乙酯。讨论了微波辐射功率、辐射时间、催化剂用量、带水剂的量及反应摩尔比等因素对酯产率的影响。最佳酯化条件为:醇酸摩尔比为2∶1,催化剂用量为乳酸用量的2.0%,带水剂15 mL,微波功率450 W,辐射时间45 min,乳酸乙酯产率可达89.2%。With lactic acid and ethanol as raw material, anhydrous calcium chloride as catalyst, ethyl lactate was synthesized under the condition of microwave irradiation and normal pressure. The effects of power and time of microwave irradiation, amount of catalyst and water carrier, and reactants ratio etc. on yield were studied. Optimal reaction condition were microwave power 450 W, irradiation time 45 min, the molar ratio of ethanol to lactic acid was 2：1 ,weight of catalyst was 2.0% of lactic acid mass, the amount of water cartier was 15 mL, and as a result, the yield of ethyl lactate reached up to 89.2%.

关 键 词：化学合成 酯化反应 乳酸乙酯 微波法 催化剂 

分 类 号：TQ225.24[化学工程—有机化工]