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机构地区:[1]石油化工科学研究院,中国石化水处理中心,北京100083 [2]同济大学环境科学与工程学院,污染控制与资源化研究国家重点实验室,上海200092
出 处:《环境科学》2013年第3期1004-1007,共4页Environmental Science
基 金:国家自然科学基金项目(50408039);国家高技术研究发展计划(863)项目(2007AA06Z326);中国石化基础科研项目(311047)
摘 要:采用基于SCFAs代谢的动力学模型,模拟了不同碳源类型和不同m(P)/m(COD)对聚磷菌(PAO)和聚糖菌(GAO)竞争的影响.结果表明,以乙酸作为唯一碳源时,EBPR中的微生物种群结构基本保持反应器初始状态的生物组成,PAO或GAO都无法取得明显的竞争优势.但是,在进水中添加丙酸有利于PAO成为优势微生物,当丙酸占总酸的质量分数达到33%以上时,EBPR趋于稳定.当m(P)/m(COD)<0.01时,即使丙酸作为EBPR的碳源,GAO仍占(PAO+GAO)总量的95%以上.为了使PAO占有优势,进水m(P)/m(COD)应该控制在0.04~0.10之间.The kinetic model based on SCFAs metabolism was applied for the prediction of phosphorus-and glycogen-accumulating organisms (PAO and GAO) competition with different carbon sources and m(P)/m(COD) ratios. When acetic acid was used as the sole carbon source, the biomass compositions were almost the same as those before cultivation, and neither PAO nor GAO could be out- competed from EBPR. However, increasing propionic acid in the influent helped PAO to be the predominance organism, and EBPR performance kept excellent when the ratio of propionate to mixed acids ( acetate + propionate) was higher than O. 33. It also found that the m( P)/m(COD) ratio should be kept at 0.04-0. 10 to avoid phosphorus became a limiting factor for PAO growth. This was because at low m (P)/m (COD) ratios, such as 0.01, GAO would take up 95% of the total (PAO + GAO) biomass.
分 类 号:X11[环境科学与工程—环境科学]
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