静态弹性成像对正常乳腺组织弹性模量的影响  

Research on effect of static elastography on the elastic modulus of normal breast tissue

作　　者：梁思[1] 钱林学[1] 刘冬[1] 

机构地区：[1]首都医科大学附属北京友谊医院超声科,北京100050

出　　处：《中国医学装备》2015年第12期66-68,共3页China Medical Equipment

摘　　要：目的:研究静态弹性成像操作对正常乳腺组织弹性模量造成的影响。方法:①对15个正常腺体型乳腺同一位置进行静态超声弹性检测,截取未压缩时的图像及最大压缩图像,测量乳腺厚度(h,cm),计算最小伸长比(λ),得出静态弹性成像正常操作对正常乳腺组织造成的变形;②对50个正常腺体型乳腺采集未进行压缩时弹性模量(E_0,kPa)及压缩所致伸长比达到第一部分所得λ时的弹性模量(E_m,kPa)。分别计算弹性模量改变比(R_(m/0)),得出静态弹性成像正常操作时正常乳腺组织弹性模量的改变。结果:静态弹性成像操作中对正常腺体型乳腺造成的最小伸长比λ=0.74±0.07,静态弹性成像中正常操作造成的变形使正常乳腺组织弹性模量增加4.38倍。结论:静态弹性成像造成正常乳腺组织弹性模量增加4.38倍。Objective：To investigate the effects of static ultrasound elastography on the elastic modulus of normal breast tissue.Methods：（l）Fifteen cases of normal breasts was tested by static ultrasound elastography at the same locations.Intercepted two pictures each time with one stressfree and the other compressed the maximum amount.For these two cases we measured the breast thickness and calculated the minimum stretch ratios（λ）.（2） Fifty breasts with no breast nodules were prospectively enrolled in the study.Intercepted two pictures each time with one stress-free and the other compressed to the minimum stretch ratios（λ）.For these two cases we measured the Elastic modulus（E_0,E_m,kPa）.Calculate the elastic modulus change ratio（R_（m/0））.Results：（1）The minimum stretch ratio caused by static ultrasound elastography was 0.74±0.07.（2）The elastic modulus change ratio of static ultrasound elastography was 4.38±1.72.Conclusion：The normal operation of static ultrasound elastography caused 74 percent deformation in normal breast tissue.There was 4.38 times elastic modular increasing caused by 74 percent deformation in normal breast tissue.

关 键 词：乳腺 超声弹性成像 弹性模量 

分 类 号：R737.9[医药卫生—肿瘤]