In [1—3], we have discussed problems on the Putnam-Fuglede theorem of non-normal operators which reduce AX=XB’(AXB=X) to A*X =XB* (A*XB* =X). For the normal operators the following problems are considered: Let ...
For bounded linear operators on a Hilbert space, we prove that the following three forms of the Putnam-Fuglede theorem are equivalent. Theorem PF. If M and N are normal operators and X is an operator, then MX=XN
In this letter, we shall prove the asymptotic Putnam-Fuglede theorem of hyponormal operators by using the Berberian technique: Let H oe a Hilbert space and Iet X={{x_n}}:{x_n} is a bounded sequence in H}.
Let B(?) denote the set of all bounded linear operators on a Hilbert space H. It is well known that normal operators of B(H) have an important property——the Fuglede-Putnam theorem. In recent years, a number of p...
It is shown in this note that the answer to Abrahamse’s Problem 3 in [1] is that the Bergman shift is not unitarily equivalent to a Toeplitz operator. Obviously, this problem should be considered before the Halmos co...
Let H be a complex separable Hilbert space and L (H) (resp. L_α (H)) be the set of all the linear bounded (resp. bounded self-adjoint) operators on H. For X, Y ∈ L_α (H), let φ, ψ be the bounded real valued Baire...