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作 者:李欣芮 李浩廷 杨润东 孙合明[2] LI Xinrui;LI Haoting;YANG Rundong;SUN Heming(College of Energy and Electrical Engineering,Hohai University,Nanjing 210000,Jiangsu,China;College of Science,Hohai University,Nanjing 210000,Jiangsu,China;College of Computer and Information,Hohai University,Nanjing 210000,Jiangsu,China)
机构地区:[1]河海大学能源与电气学院,江苏南京210000 [2]河海大学理学院,江苏南京210000 [3]河海大学信息学部,江苏南京210000
出 处:《能源与节能》2023年第12期26-29,57,共5页Energy and Energy Conservation
摘 要:主要研究在波浪激励的作用下,一种波浪能装置在实际工作中的运动规律。对波浪能装置,建立了基于牛顿三大定律和胡克定律的刚体运动模型,先仅考虑了在竖直方向上的一维运动微分方程,再考虑装置的平面运动。将装置的浮子和振子视为两个刚体,每个刚体的运动可以转化为平面上的平动和转动。这2个刚体的运动规律可用6个微分方程进行描述。据装置的工况,得出微分方程的初始条件,后采用4阶Runge-Kutta方法求解微分方程,得出浮子和振子的运动规律,进而推导出稳定条件下,波浪能装置的输出功率,并且给出了在一定条件下装置输出最大功率时的阻尼系数。The motion law of a wave energy device in practical work under the action of wave excitation was mainly studied.For wave energy devices,a rigid body motion model based on Newton's three laws and Hooke's law was established,first considering only the one-dimensional motion differential equation in the vertical direction,and then considering the planar motion of the device.Consider the float and oscillator of the device as two rigid bodies,and the motion of each rigid body can be transformed into translation and rotation on a plane.The motion laws of these two rigid bodies can be described by six differential equations.Based on the operating conditions of the device,the initial conditions of the differential equation were obtained,and then the 4th order Runge-Kutta method was used to solve the differential equation.Obtain the motion laws of the float and oscillator,then deduce the output power of the wave energy device under stable conditions,and provide the damping coefficient at the maximum output power of the device under certain conditions.
关 键 词:牛顿运动定律 微分方程 4阶Runge-Kutta方法 平面运动
分 类 号:TK79[动力工程及工程热物理—流体机械及工程]
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