求留数的另一方法  

Other method that resolves the residue

作　　者：孟祥发[1] 

机构地区：[1]天津理工学院职业技术学院,天津300380

出　　处：《天津理工学院学报》2001年第2期4-5,共2页Journal of Tianjin Institute of Technology

摘　　要：介绍一个求留数的简便方法 :当z0 为函数 f(z)的n级极点时 ,可取大于n的正整数m ,用如下公式计算函数 f(z)在z0 点的留数 :Res[f(z) ,z0 ]=1(m - 1 ) !limz→z0dm- 1dzm- 1 {(z-z0 ) mf(z) }.This paper chiefly introduces a simple method that can resolve the residue :When z 0 is the function f(z)'s pole of order n, we can use the positive integer m that is bigger than the positive integer n, to calculate the residue of the function f(z) at z 0 with the formulation listed in the following:  Res =1(m-1)! lim z→z 0 d m-1 d z m-1 {(z-z 0) mf(z)}.

关 键 词：留数 极点 洛朗级数 函数 

分 类 号：O174.5[理学—数学]