植物乳杆菌的功能评价  

Gastrointestinal survival and beneficial properties in vitro of Lactobacillus plantarum strains

作　　者：熊强[1] 王凯[1] 王延斌[1] 

机构地区：[1]南京工业大学食品与轻工学院,江苏南京211800

出　　处：《生物加工过程》2016年第6期46-53,共8页Chinese Journal of Bioprocess Engineering

基　　金：江苏省重点研发项目(BE2015305)

摘　　要：从实验室自制泡菜中分离得到6株乳酸菌,经生理生化试验和分子生物学鉴定为植物乳杆菌(Lactobacillus plantarum)。对6株植物乳杆菌进行评价,发现1株环境耐受能力较强、益生效果较好的植物乳杆菌Z22,其在人工胃液和肠液中的存活率分别为95.45%和45.24%,胆固醇脱除率为65.80%。植物乳杆菌Z22胞外多糖的抗氧化试验结果表明:酸性多糖EPS-S对1,1-二苯基-2-三硝基苯肼自由基(·DPPH)、·OH、超氧阴离子自由基(·O-2)均有较好的清除能力,分别达到27.75%、66.16%和58.00%;中性多糖EPS-Z对这3种自由基清除率分别为24.02%、59.03%和45.20%,且EPS-S的抗氧化能力要高于EPS-Z。Six lactic acid bacteria were isolated from fermented vegetable made in the laboratory, and identified as Lactobacillus plantarum by physiological, biochemical and molecular biology tests. L. plantarum Z22, one of six strains of L. plantarum, had strong gastrointestinal resistance, with the survival rate was 95.45% in the simulated intestinal juice and 45.24% in gastric juice. The strain could remove 65.80% cholesterol in vitro. The extracellular polysaccharide EPS-S and EPS-Z of L. plantarum Z22 could scavenge 1,1-diphenyl-2-picrylhydrazyl radical （· DPPH ）, hydroxyl radicals （· OH） and super- oxide anion radicals （· O2-） ,the scavenge rates were 27.75% ,66. 16%,58.00% and 24.02% ,59.03%, 45.20% ,respectively.The antioxicant activity of poly saccharide EPS-S is higher than that of EPS-Z.

关 键 词：植物乳杆菌 胞外多糖 抗氧化 

分 类 号：TS252.1[轻工技术与工程—农产品加工及贮藏工程]